please sovle this question if u cant????

Question

A proton (mass 1u) moving at 6.90 Mm/s collides elastically and head-on with a second particle moving in the opposite direction at 2.80 Mm/s.after the collision,the proton is moving opposite to its initial direction at 8.62 Mm/s.FInd the mass and final velocity of the second particle???

please solve to equetion plz

Answer 1

You have 2 unknowns: the mass (m2) and final velocity (v2) of the 2nd particle.

2 unknowns require 2 equations to solve for the unknowns. These 2 equations come from:
1) conservation of momentum: m1v1 + m2v2 = m1v1' + m2v2'
2) conservation of energy:
1/2m1v1^2 + 1/2 m2v2^2 = 1/2m1v1'^2 + 1/2m2v2'^2

1) 1u * 6.9 Mm/s - m2 * 2.8 Mm/s = -1u * 8.62 Mm/s + m2*v2

2) (1/2 * 1 * 6.9M^2) + (1/2 * m2 * 2.8M^2) =
(1/2 * 1 * 8.62M^2) + (1/2 * m2 * v2^2)
(units omitted for clarity)

If you still can't solve these 2 equations for the 2 unknowns (m2 and v2), then edit your anwerer and add addtional details (to ask us to solve them for you).

.

Answer 2

in english i dnt speak ****