Chem Question?

1 ⤊

What is the change in internal energy (in J) of a system that releases 612 J of thermal energy to its surroundings and has 515 cal of work done on it? Show work

2007-10-17 04:10:31 · 3 answers · asked by bumblebee 4 in Science & Mathematics ➔ Engineering

3 answers

Change in energy is equal to the energy added less the energy released.

Delta E = E in - E out

= 515 cals - 612 Joules

= 515 cals *(4.184 joule/cal) - 612 Joules

= 2154 joules - 612 Joules

= 1543 joules

2007-10-17 06:23:43 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 1⤊ 0⤋

515cal x 4.184J/cal = 2,155J
2155 - 612 = + 1,543J change of themal energy.

2007-10-17 19:33:03 · answer #2 · answered by Norrie 7 · 0⤊ 0⤋

93 J

2007-10-17 11:14:22 · answer #3 · answered by Anonymous · 0⤊ 1⤋