how many sq. ft. for a 5000 seat arena with a field 150x300? with an eve heigth of 18 ft.how many seats?

Answer 1

See, there's this thing called math. Anyone can do it. Enjoy.

Answer 2

You really haven't given enough information here - I would have to assume that there is a height difference of about 15 inches height between rows (two steps between rows in the aisles), the final row at the top requires a minimum 8 foot clearance from the floor to the ceiling, and the horizontal spacing for each row is about 30 inches. I also have to assume that these are just bench seats, like steps.

That being set, divide the remaining 10 foot height by 1.25 feet per row, giving eight rows of seats on the four rectangular sides of the field. They would take up a total width of 9 x 2.5 feet per row (one extra needed at the bottom) or 22.5 feet, let's say 23 feet to allow for passage along the bottom row. So the horizontal area occupied by the seats would be 23' x 300' for the sides, and 23' x 150' for the ends. Total area for those seats would be 23(300+300+150+150) = 23x900 = 20,700 square feet. The field itself is 45,000 square feet.

There are also the four corners to consider. In an arena, these would be in the shape of quarter-circles, but the four of them would make up a complete circle with a radius of 23 feet. The area of that circle would be 3.14x23x23 or about 1660 square feet. The total would be 20,700 + 45,000 + 1660 = 67,360 square feet. This does not allow for any exterior wall "footprint", of course, so it's just the interior area.