how do you power a light bulb with a battery?

Question

science fair

Answer 1

Just connect the positive terminal of the battery with one electrical contact of your light bulb and the negative terminal with the other electrical contact of the bulb. Many bulbs have one electrical contact with screw threads on it, with the other contact as a round dot on the end of the base. Other bulbs will have metal prongs sticking out. It’s notoriously hard to get good electrical contact on batteries and bulbs by soldering wires on. The spring contacts in flashlights work much better (but even they are troublesome from time to time).

It’s important to select a bulb which matches what your battery can put out. If the battery has too low a voltage, the current flowing through the bulb will be small and the bulb’s filament won’t get hot enough to visibly glow. If the battery has too high a voltage, so much current will flow that the filament will get too hot and vaporize.

Standard bulbs are designed to work with a voltage of around 120 V, which is an unusual range for batteries. Ordinary flashlight bulbs are designed to work with about 3V, easy to obtain with two batteries in series. Bulbs from cars are usually designed to work with about 12V, the output of a car battery or of eight standard battery cells in series.

You might think that using a lower voltage would only slightly dim the light, but actually the effect is much more severe. First, the heating power in the bulb goes as the square of the voltage, at least until the voltage gets big enough for the bulb to heat up and increase its resistance. Second, the amount of visible light produced in the bulb is virtually zero until the filament temperature gets close to the standard operating temperature. Thus using one fourth of the power will give much less than one fourth of the light output. If you use a bit too low a voltage, the bulb will glow orangeish, because it can still put out some colors of light but not the blue part of the spectrum.

Hope this helps :)

Answer 2

ok simple
(no switch way)
two cables you need, a bulb and battery
get one cable
connect to one terminal of battery and 1 side of bulb
do same with other cable
(switch way)
things u need
switch and other stuff from before
3 cables remember
first
on the switch there is a section labelled core
connect a wire from the battery to core
way 1
put a cable leading to bulb in there
get the last cable and put it on the core and bulb
there
the bulb should light up

Answer 3

Connect it to the battery by connecting the positive and negative terminals of the battery to either side of lightbulb's connections. The resistance of the wire inside the lightbulb will give off the energy given by the current provided from battery as light energy.

Answer 4

2 leads from the - & + terminals to the bulb itself. The side of the bulb and the base of it. Very simple.

Answer 5

is this a call for set by potential of your instructor? if so, is he or she insane? To get to one hundred twenty volts you will need approximately 80 5 D, C, or AA cells in sequence (they grant a pair of million.4 volts below load, divide one hundred twenty by potential of a million.4). or you'll be able to desire to apply approximately 13 9-volt batteries in sequence. i might make it 15, when you consider that they gained't shelter 9 volts for long. Now 50 watts at one hundred twenty volts is slightly below a million/2 an amp. a series of respectable NiMH AA batteries could be waiting to grant a million/2 an amp for 2 hours. they're costly yet a minimum of you may recharge and so reuse them. of direction, recharging 80 5 batteries will take it slow, till you purchase multiple chargers, which will upload to the value. in case you utilize alkaline D cells you'll be able to get a million/2 an amp from them for extra or less 20 hours. Alkaline AA cells, perhaps 3 hours. by potential of that element the two form could be right down to in basic terms 0.8 volts and the bulb could be somewhat dim. 9-volt batteries are even worse. At a million/2 an amp a 9-volt will "run" for a pair of million/2 an hour, whether we are in a position to tolerate its voltage dropping to 4.8 volts, it relatively is tremendously ineffective for this pastime. i might say you will get no extra advantageous than 10 minutes of useful brightness out of 9-volts used this way. i might advise a lots decrease wattage bulb. The 7 watt "candelabra" bulbs could be sturdy. extra ideal yet, use a flashlight bulb, that gets rid of the will for best voltage. (one hundred twenty volts DC isn't fairly secure to artwork with... safer than one hundred twenty AC could be, yet nonetheless not secure, fairly for somebody not fairly knowledgeable interior the sphere.) nonetheless extra ideal: Use LEDs, which will provide far extra easy for a given quantity of potential and could not want this way of severe voltage. you will desire a minimum of one sequence resistor, although. examining different replies... no, uncomplicated 120V incandescent easy bulbs do not want AC. they're going to artwork positive on DC. that's basically getting the voltage it relatively is the project. The unit that takes 12 volts from a vehicle battery and produces 120VAC is stated as an "inverter". sure, that could desire to artwork and for many longer than the stack of alkaline batteries. yet you will additionally be lugging this heavy vehicle battery around. i like the belief of utilising the vehicle headlamp. or in line with threat a vehicle taillight bulb.

Answer 6

Military Grade Tactical Flashlight - http://FlashLight.uzaev.com/?aGbG

Answer 7

take foil and tape in ti one end of a battery and take another peice of foil and tape it to the other end of a battery, then tape the two pieces of foil to the bottom of the light bulb

Answer 8

you need, wires, bulb, battery, and crocodile clips. Build them all together.

Answer 9

build a circuit