A 10 meter long beam is supported on the ends. It has a mass of 980 kg, and 2 loads: load 1 is placed 2 meters from the left end and is 1500 kg in mass, load 2 is placed 4 meters from the right end and is 3500 kg in mass.
Frleftend=___N
Frrightend=___N
2007-10-11 19:30:17 · 2 answers · asked by Kiwi K 1 in Science & Mathematics ➔ Physics
Sorry. Even if I was strong in math and measurements, I would not do somebody elses homework.
2007-10-11 19:37:25 · answer #1 · answered by mgctouch 7 · 0⤊ 0⤋
Total mass = 5980 kg
Total force acting down = 5980 kg f.
1kg f = 9.8 N ~10N.
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F1 be acting up on the left end and F2 be acting on the right end.
For equilibrium,
F1 + F2 = 5980 kg f
And moments about any point must be zero.
Taking moment about the left end,
F2 x 10 = 3500 x 6 + 980 x 5 + 1500 x 2
Hence F2 = 2890 kg f or 28900 N
Taking moment about the left end,
F1 x 10 = 3500 x 4 + 980 x 5 + 1500 x 8
Hence F1 = 3090 kg f or 30900 N
2007-10-12 02:30:45 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋