(2^4)*(3^2)*5
2007-10-11 18:41:28
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answer #1
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answered by Phineas Bogg 6
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2 x 2 x 2 x 2 x 3 x 3 x 5
2007-10-12 01:42:45
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answer #2
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answered by Harsh Saini 2
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20 x 36
4 x 5 x 4 x 9
2 x 2 x 2 x 2 x 3 x 3 x 5
2^4 x 3² x 5
2007-10-12 09:58:34
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answer #3
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answered by Como 7
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720 is not a prime number.
The prime factorization of 720 = 2^4 • 3^2 • 5
2007-10-12 01:54:40
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answer #4
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answered by Christine P 5
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2^4 x 3^2 x 5^1
2007-10-12 01:42:40
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answer #5
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answered by LeOsCarZ 1
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720 / 2 = 360
360 / 2 = 180
180 / 2 = 90
90 / 2 = 45
45 / 3 = 15
15 / 3 = 5
Prime factors of 720 are:
= 2 * 2 * 2 * 2 * 3 * 3 * 5 or
= 2^4 * 3^2 * 5 or
= (2 * 3)^2 * 2^2 * 5
2007-10-12 02:47:40
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answer #6
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answered by Jun Agruda 7
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2^4 * 3 ^2 * 5
2007-10-12 01:42:05
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answer #7
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answered by Pune 1
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2â720
2â360
2â180
2â90
2â45
3â15
3â5
5â5
Therefore the prime factorization of 720 is 2,2,2,2,2,3,3,5
= 2^5 x 3^2 x 5
2007-10-12 01:44:36
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answer #8
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answered by Anonymous
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720 =
2*2*2*2*3*3*5
2007-10-12 01:42:32
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answer #9
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answered by Quocamus 2
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Just brute force divide by every prime number until you can-
t do anymore. 720 is 6! so it contains the first three primes
720/2xxxx45/3 2.2.2.2.3.3.5=720
360/2xxxx15/3
180/2xxxx5
90/2xxxxxx
45
2007-10-12 01:47:44
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answer #10
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answered by jim m 5
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