(x-7)(x-8) - (x-9)^2 = 12?

Question

(x-7)(x-8) - (x-9)^2 = 12

please help!!!! =[

Answer 1

(x-7)(x-8)-(x-9)^2=12

=> [x(x-8)-7(x-8)] - (x^2-18x+81) = 12

=> (x^2-8x-7x+56) - (x^2-18x+81) = 12

=> (x^2-15x+56) - (x^2-18x+81) = 12

=> x^2-x^2-15x+18x+56-81 = 12

=> 3x-25 = 12

=> 3x = 12 +25

=> 3x = 37

=> x = 37/3

=> x = 12.3

Solution of x = 37/3 i.e. 12.3

Answer 2

(x - 7)(x - 8) - (x - 9)^2 = 12
(x^2 - 8x - 7x + 56) - (x^2 - 9x - 9x + 81) = 12
(x^2 - 15x + 56) - (x^2 - 18x + 81) = 12
x^2 - 15x + 56 - x^2 + 18x - 81 = 12
3x - 25 = 12
3x = 37
x = 37/3

Answer: x = 37/3 or 12 1/3

Proof:
(12 1/3 - 7)(12 1/3 - 8) - (12 1/3 - 9)^2 = 12
(5 1/3)(4 1/3) - (3 1/3)^2 = 12
(16/3 * 13/3) - (10/3)^2 = 12
208/9 - 100/9 = 12
23 1/9 - 11 1/9 = 12
12 = 12

Answer 3

Multiply things out to get:

x^2 - 15x + 56 - (x^2 -18x+81) = 12

simplify to get:
3x - 25 = 12
3x =37
x = 37/3

Answer 4

(x - 7)( x - 8) - (x - 9) ^ 2 = 12
on simplification becomes
x^2 -15 x +56 - x ^ 2 +18 x - 81 = 12
or
3x -37 = 0
therefore x is 37 / 3

Answer 5

(x-7)(x-8) - (x-9)^2 = 12
x^2 -15x + 56 - ( x^2 -18x +81) = 12
3x -25= 12
3x= 37
x = 12.333 ( 12 and a third)

Answer 6

(x-7)(x-8) - (x-9)^2 = 12

(x^2 - 15x + 56 -[x^2 - 18x +81] = 12

x^2 -15x + 56 - x^2 + 18x - 81 - 12 = 0

3x -37= 0

x = 37/3

Answer 7

x^2 - 15x + 56 - (x^2 - 18x + 81) = 12
x^2 - 15x + 56 - x^2 + 18x - 81 = 12
3x - 25 = 12
3x = 37
x = 37/3

Answer 8

First, subtract 8 from ninety two and additionally you get 80 4. From there 7x equals 80 4 so which you're able to be able to desire to simplify it so which you try this via dividing 7 into 80 4 and additionally you get 12. once you're questioning the artwork could desire to look like this: 8+7x=ninety two -8 - 8 ____________ desire that helped you for passing algebra one million ^-^ 7x= 80 4 7x/7= 80 4/7 x=12

Answer 9

x ² - 15x + 56 - (x² - 18x + 81) = 12
3x - 25 = 12
3x = 37
x = 12 ⅓