A model for the velocity of the shuttle from liftoff at t=0 s until the solid rocket boosters were jettisoned at t=61.3 given by
v(t)=0.001149000t^3-0.08519t^2+12.52t-9.76
please find
the absolute maximum value
the absolute minimum value
of the acceleration of the shuttle between liftoff and the jettisoning of the boosters
2007-10-11 17:59:58 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You need to take the derivative to get the acceleration. I'd start there.
Minimum velocity will be -9.76 m/sec at lift off. Maximum velocity will be at separation. You can figure this out by looking at the acceleration curve and seing that it is positive all the way up to seperation. Just plug in the t value of 61.3.
2007-10-11 18:15:52 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 1⤊ 0⤋
the acceleration is the differentiation of v(t)
so a(t)=v'(t)
but I see that the v(t) eq is not complete (the ... after the ^2)
2007-10-12 01:10:03 · answer #2 · answered by Maurizio G 2 · 0⤊ 0⤋