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Ok, so this is very stupid. Please tell me how to do it.

Lim as n->infinity of a_n= ( 1/ ( e^(4n) +n^2) )^ (1/n)

Apparently the answer is not 0, 1/e, or 1. Go figure.

2007-10-11 17:19:47 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

[n→∞]lim ( 1/ ( e^(4n) +n^2) )^(1/n)
[n→∞]lim 1/ ( e^(4n) +n^2)^(1/n)
1/[n→∞]lim (e^(4n) +n^2)^(1/n)
1/[n→∞]lim (e^(4n))^(1/n) (n² term is negligible next to e^(4n)
1/[n→∞]lim e^4
1/e^4
e^(-4)

2007-10-11 17:27:57 · answer #1 · answered by Pascal 7 · 0 0

no solution after about 50 you get error on your calculator

2007-10-11 17:27:34 · answer #2 · answered by Anonymous · 0 0

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