Calculate the change in free energy (KJ) for the reaction NO(g) + O3(g) → NO2(g) + O2(g)?

Question

Calculate the change in free energy (KJ) for the reaction
NO(g) + O3(g) → NO2(g) + O2(g) under the following conditions T = 298 K ΔGo = -198.0 kJ/mol

Pressure of NO = 1.72 x 10-5 atm
Pressure of O3 = 1.58 x 10-5 atm

Pressure of NO2 = 2.90 x 10-6 atm
Pressure of O2 = 2.25 x 10-2 atm

Answer 1

Applying the following formula:
ΔG = ΔGo + kT Ln Q
= -198.0 + 8.314x10^-3*298*Ln((2.90 x 10-6)(2.25 x 10-2)/(1.72 x 10-5)(1.58 x 10-5))
= -198.0 + 13.6
= -184.4 (kJ/mol)