What is the period of oscillation for a guitar string that produces a sound wave with a frequency of 880 Hz?

Answer 1

in order to solve this problem you need to use the formula: t=1/f. Since the frequecny of a wave is equal to the reciprocal of the period. (T stands for the period). So your equation should look like this: t=1/880. Your answer should be .001136 oscillations a second.

Answer 2

The period is the inverse of the frequency, i.e. the period = 1 / (880 cycles/sec) = 1/880 sec = 1.14e-3 sec.

Added: Daniel is correct - reciprocal, not inverse; however, I am correct in my units of the period = time, not frequency...

So with the help of both of us, you're closing in on it!