A man and a woman each have dark eyes, dark hair and freckles. The woman is heterozygous for each trait while the man is homozygous for each trait. What are the chances their baby will have dark eyes, dark hair and freckles. What are the chances their baby will have the genotype as the father? What are the chances their baby will have the same genotype as the mother?
B=dark eyes b=blue eyes
H=dark hair h=blond hair
F=freckles f=no freckles
2007-10-11 15:16:38 · 2 answers · asked by damigurl05 1 in Science & Mathematics ➔ Biology
Woman: Bb Hh Ff
Man: BB HH FF
Chances of the baby having:
Dark eyes = 100%
Dark hair = 100%
Freckles = 100%
Why? Because the father has two copies of each of these dominant alleles, and therefore his only "option" is to pass a dominant allele onto his child.
See charonnisis's answer below regarding the probability of having the same genotype as either parent.
Punnett squares would help you solve these kind of problems in the future. Go to: http://www.athro.com/evo/gen/punexam.html
2007-10-11 15:24:48 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Since the father is Homozygous, and all 3 are Dominiant traits, there is 100% that the offspring will have those characteristics. The chance of being the same geneotype os the father is (1/2)*(1/2)*(1/2)=1/8 or 12.5% chance of matching teh father. It is the SAME for matching teh mom= 12.5%.
2007-10-11 23:38:07 · answer #2 · answered by charonnisis 3 · 0⤊ 0⤋