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Math problems System of linear equation in two variables

2x-5y=3
-4x+10y=3

2007-10-11 15:11:56 · 3 answers · asked by ydfarm 2 in Science & Mathematics Mathematics

3 answers

2x - 5y = 3 eqn 1
-4x + 10y = 3 eqn 2

eqn 2 can also be written as
-2x + 5y = (3/2) .....dividing both sides by 2

or 2x - 5y = - (3/2) eqn 3


hence eqn 1 and eqn 2 and not consistent.....that is even though they have same left hand side their right hand side is different....
so this is not a consistent system of equation....
this is the solution
u cannot solve it because the equations are not consistent.


HOPE THIS HELPS

2007-10-11 15:18:05 · answer #1 · answered by live n let live 3 · 0 0

2x - 5y = 3
-4x + 10y = 3
Combine both equations:
2x - 5y = -4x + 10y
Collect like terms on opposite sides:
2x + 4x = 10y + 5y
6x = 15y or 2x = 5y
Substitute in #1:
5y - 5y = 3
Substitute in #2:
-10y + 10y = 3
Obviously makes no sense, check you copied the question.

2007-10-11 15:23:00 · answer #2 · answered by Robert S 7 · 0 0

solve first the value of y.GIven:A1=2,A2=-4,B1=-5,B2=10,K1=3,K2=3.Formula:y=(A1xK2)-(A2xK1)/(A1xB2)-(A2-B1).Substitute,Y=(2x3-(-4)x3) divide by(2x10-(-4x5),Y=6-(-12) divided by 20-(-20),Y=18/40,Y=0.45.So we can now solve the value of x by subtituting the value of y which is 0.45.Solve it for self and check the equation.

2007-10-11 16:02:31 · answer #3 · answered by kamote 1 · 0 1

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