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Find A + B if ((n^3)+1)/((n^2)+2n = n - 2 + (A/n) + (B/n + 2).

2007-10-11 15:05:01 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

I think you lost a ")". They were unbalanced. So I add one below where I thought it should go

Find A + B if ((n^3)+1)/((n^2)+2n) = n - 2 + (A/n) + (B/n + 2).
((n^3)+1)/((n^2)+2n) = n - 2 + (A/n) + (B/n + 2)
((n^3)+1)/(n*(n+2)) = n - 2 + (A/n) + (B/n + 2)
n^3+1 = (n^3+2n^2)- (2n^2+4n) + A(n+2) + Bn
n^3+1 = n^3-4n+ A(n+2) + Bn
1 = -4n+ An+A2 + Bn
1=n(A+B-4) +A2
A+B=4+(1-2A)/n

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This seems inelegant compared to the other 2 of your problems I did after this. Possibly I got the problem as I wrote it is wrong, or I made a mistake.

2007-10-11 15:49:41 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 1 0

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