Calculate the mass in grams of 2.3456 mol of lead. Calculate the number of moles of 2.3456 g of lead.?

Question

I'm so lost. Please explain the steps that you did. And, of course, the answer. lol.
Thank you!

Answer 1

This is very simple, you just need to multiply the weight for 1 mole of lead by the number of moles. This weight you get right from the periodic table; for lead I find 207.2g/mole.

So the mass of 2.3456 moles would be:

2,3456mol x 207.2g/mol = 486g

To do the 2nd part is also simple, just divide the number of grams specified by the weight of one mole of lead.

2.3456g/207.2g/mol = 0.0113 mole

Unlike what the first answerer says, sometime we are helping you during the test, because people just use their cell phone with wireless internet to post the test questions on YA (during the exam) and get them answered in time!

Answer 2

Al2S3 + 6H2O --> 2Al(OH)3 + 3H2S Having the balanced equation describing the reaction, the subsequent step is calculating the variety of moles. The molecular weight of Al2S3 is what a million mole of its molecules weighs. this could be the sum of the atomic weights of the atoms interior the molecule. For Al2S3, the load could be 27*2 + 32*3 = a hundred and fifty grams according to mole. subsequently 2 hundred grams could be 2 hundred grams / (a hundred and fifty grams/mole) = a million.333 moles. The variety of moles of water obtainable is a hundred and fifty grams / (18 grams/mole) = 8.33 moles. Now, learn the molar ratios from the balanced equation. a million mole of Al2S3 demands 6 moles of H2O to variety 3 moles of H2S. From the calculations above, a million.333 moles Al2S3 might require 8 moles of water. There are 8.33 moles obtainable, so there is greater desirable than sufficient to variety the product. The molar ratio of Al2S3 to H2S is a million to 3, so a million.33 moles will variety 4 moles of H2S. 4 moles of H2S weighs 4 moles * (34 grams/ mole) = 136 grams.

Answer 3

If the precise calculation of mass is equated with the calculated number of moles, the parallel congruity of the weighted measures will be bilaterally equal unless the opposite weight attraction factor is present.

Answer 4

o.k... you are pushing it, go read a chemistry book and do your own home work. Remember that the members of Yahoo Answers will not be there to help you in an exam.