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Part 1)
The initial speed of a body is 8:08 m/s.
What is its speed after 1.54 s if it accelerates
uniformly at 3:03 m/s2? Answer in units of
m=s.

Part 2)
What is its speed after 1.54 s if it accelerates
uniformly at -3.03 m/s2? Answer in units of
m=s.

2007-10-11 14:24:20 · 2 answers · asked by Jarod S 2 in Science & Mathematics Physics

2 answers

v(t)=vi+a*t

1) v(1.54)=8.08+3.03*1.54

2) v(1.54)=8.08-3.03*1.54

j

2007-10-12 05:14:50 · answer #1 · answered by odu83 7 · 0 0

Relative speed of trains(u) = 30 + 30 = 60 km/hr =>time of collision (t) = s/u = 60/60 = a million hour =>hence the gap lined by utilizing chicken (s) :- =>by utilizing s = v x t =>s = 60 x a million = 60 km

2016-10-20 06:49:04 · answer #2 · answered by rothi 4 · 0 0

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