okay does ANYONE know how to balance this equation?
*#* are subscripts... the numbers usually written on bottom
---> is yields or equals
Ca(OH)*2*+HNO*3* ----> Ca(NO*3*)*2*+H*2*O
2007-10-11 14:03:57 · 5 answers · asked by psh... 1 in Science & Mathematics ➔ Chemistry
OMG someone else wrote that answer too... but Huda O... i can't belive it! thats right! i tryed this for half an hour and couldnt get it cuz i was trying to add a coefficent infront of the first Ca!!! i can't believe it's so simple!
2007-10-11 14:35:27 · update #1
Calcium is in the +2 oxidation state; OH has a -1 charge NO3 also has a -1 charge; so you need 2 NO3 groups to get a balanced equation with calcuim.
Ca(OH)2 + 2 HNO3 ----> Ca(NO3)2 + 2 H2O
2007-10-11 14:10:47 · answer #1 · answered by Flying Dragon 7 · 0⤊ 0⤋
It's an ionic exchange reaction:
Ca++ (OH-)2 + H+ (NO3-) --> Ca++ (NO3-)2 + H+ (OH-)
You need 2 OH- or NO3- groups for each Ca++, but only 1 OH- or NO3- for each H+. That allows you to calculate how much of each ion or ion group has to be on each side to balance.
2007-10-11 21:16:32 · answer #2 · answered by John R 7 · 0⤊ 0⤋
1 2 1 2, corresponding to the four compounds
sometimes it helps if you look at H2O as HOH
2007-10-11 21:08:00 · answer #3 · answered by xzorion54 5 · 0⤊ 0⤋
all you need is a "2" in front of the second reactant..."HNO*3*"
2007-10-11 21:07:32 · answer #4 · answered by Coolio A 5 · 0⤊ 0⤋
your answer is this equation:
Ca(oH)2 +2HNo3 --------> Ca(No3)2 +2H2o
2007-10-11 21:17:21 · answer #5 · answered by huda o 1 · 0⤊ 0⤋