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A 82 kg clock initially at rest on a horizontal floor requires 618 N horizontal force to set it in motion. After the clock is in motion, a horizontal foce of 561 N keeps it moving with a constant velocity.
The acceleration of gravity is 9.81 m/s^2.

A) Find μs between the clock and the floor.
B) Find μk between the clock and the floor.

Thanks for the help!!!!!

2007-10-11 10:33:02 · 1 answers · asked by jon s 2 in Science & Mathematics Physics

1 answers

A. m*g*μs=618
μs=618/(82*9.81)
=0.768
B. m*g*μk=561
μk=561/(82*9.81)
=0.697
j

2007-10-11 10:38:20 · answer #1 · answered by odu83 7 · 2 0

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