2007-10-11 09:54:15 · 11 answers · asked by Anonymous in Entertainment & Music ➔ Polls & Surveys
You don't really think we'd let you get away that easy do ya? We will find you...OH YES...we WILL find you!!! In the words of Dale from King Of The Hill..."You may not know who I am...but I know where you live!!!" LOL LOL LOL *Hugs Babe* =D
2007-10-11 13:14:23 · answer #1 · answered by F-1 says KISS IT! 7 · 2⤊ 0⤋
If that is what pushes your buttons then by all means flush. But your contacts and fans if they are real and true will always try to find a way to find you but you would be officially free as well.
2007-10-11 10:44:55 · answer #2 · answered by Dave aka Spider Monkey 7 · 2⤊ 0⤋
Flush your contact and fan network, then turn in your acount to the administrators, then you'll be free from Yahoo! Answers.
I really hope you aren't actually considering this.
2007-10-11 10:04:01 · answer #3 · answered by Sharon Newman (YR) Must Die 7 · 1⤊ 0⤋
purely once Yahoo answer Authority bumped off one among my solutions, though I did allure. component is this one has the right to 'low score/extreme score'. it truly is their understanding(!) to judge. by no skill imagine that 'someone' doing those deliberately or out of jealousy.
2016-10-09 01:16:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
If your contacts are what's keeping you here, yes.
2007-10-11 10:01:57 · answer #5 · answered by Miss T 7 · 1⤊ 0⤋
Aghhh! Are you crazy?!! Don't flush us just to be free! :)
2007-10-11 10:17:26 · answer #6 · answered by Alaska 6 · 0⤊ 0⤋
no, i will hunt you down...lol.j/k
you just have to let go of y/a, igore the whole thing!
2007-10-11 12:53:31 · answer #7 · answered by Anonymous · 0⤊ 0⤋
No. Your friends will hunt you down. Trust me on this. }:>
2007-10-11 10:41:36 · answer #8 · answered by Ja'aj };> 6 · 0⤊ 0⤋
nope!cause you know that i would find you and make you my contact again!:)
2007-10-11 10:45:08 · answer #9 · answered by ....FED UP............ 7 · 0⤊ 0⤋
You can flush
but
you can never leave
2007-10-11 10:27:08 · answer #10 · answered by ? 6 · 1⤊ 0⤋