A 2.5Kg block initially at rest is pulled to the right along a horizontal, frictionless surface by a constant,

Question

horizontal force of 19.2N. Find the speed of the block after it has moved 4.9m. answer in units of m/s.

Answer 1

This interesting.... I wonder if there is trick.

V=at
t=sqrt(2S/a)
a=F/m

I'm prespiring in anticipation of discovering an intellectual pitfall.

so finally
V=F/m sqrt(2Sm/F)
V=sqrt(2 S F/m)
V=sqrt(2 x 4.9 x 19.2/2.5)
V= 8.68 m/s