If an intravenous solution contains 4 percent mannitol how many milliliters of the solution should be administered to provide a patient with 80 grams of mannitol?
2007-10-11 06:45:45 · 4 answers · asked by whisper2ya 2 in Science & Mathematics ➔ Mathematics
1st the statement 4 % mannitol is wrong it may be 4 gm %
that means in every 100 ml of the solution there is 4 gm of mannitol
so assuming that
100 ml ------>4 gm
???------------>80 gm
so it is 100 * 80 /4 =2000 ml ,i.e 2 liters (he will enjoy it :))
2007-10-11 07:13:41 · answer #1 · answered by mbdwy 5 · 0⤊ 0⤋
Well, assuming mannitol and the solution have the same density (problematic at best), the answer is 2000 mL. One mL of solution will have 0.04g, so 80/.04=2000.
2007-10-11 06:53:50 · answer #2 · answered by alb_4 3 · 0⤊ 0⤋
It depends on the density of mannitol.
Anyway the answer will be 80/(0.04 x Density of Mannitol)
This is assuming that density is given in grams/milliliter.
If it isn't you will have to convert to grams/milliliter first.
2007-10-11 06:58:45 · answer #3 · answered by zenock 4 · 0⤊ 0⤋
This is not a math question. It seems a chemistry question. You must know how many grams/milliliters the mannitol has.
2007-10-11 06:52:45 · answer #4 · answered by Escatopholes 7 · 0⤊ 1⤋