2007-10-11 05:34:07 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You have [2a^(-2)b^3]^4 / [(a^3)b]^2
Multiply it all out, you get
[16a^(-8)b^12] / [a^6b^2]
16a^(-14)b^10
or
16b^10 / a^14
2007-10-11 05:39:44 · answer #1 · answered by mathguru 3 · 0⤊ 0⤋
(2a²b³)⁴/ (a³b)²
1. distribute the exponents appropriately so ou can eliminate the parentheses:
2⁴a^8b^12 / a^6b²
2. cancel out and simplify. if it helps, rewrite it out like so:
16aaaaaaaabbbbbbbbbbbb/aaaaaabb
3. 6 of the a's cancel from the bottom and the top, and 2 of the b's cancel from the bottom and top. you are left with: 16a²b^10
2007-10-11 05:44:50 · answer #2 · answered by Nilly 3 · 0⤊ 0⤋
Reading question as:-
2a^(-2)b³ / (a^6 b²)
2b / a^8
Or is the 1st bracket to the power 4?
If so:-
16 a^(-8)b^(12) / a^6 b²
16 b^(10) / a^(14)
2007-10-11 06:09:29 · answer #3 · answered by Como 7 · 0⤊ 0⤋