-20a^3+15a+13a^2
thanks. I am stuck on this one!!
2007-10-11 05:29:36 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First factor out the value "-a"
(20a^2 - 13a +15)-a
Now look for factors of 20 and 15 that when cross multiplied leave 13
(4a - 5) (5a + 3)a
2007-10-11 05:40:06 · answer #1 · answered by Brian K² 6 · 0⤊ 0⤋
-20a^3+15a+13a^2=0
by factoring it by -20a, we have
-20a (a^2 -13/20 a - 3/4) = 0
-20a (a - 5/4) (a + 3/5) = 0
values of 'a' are:
a = 0
a = 5/4
a = -3/5
2007-10-11 12:46:18 · answer #2 · answered by mad_vlad 2 · 0⤊ 0⤋
It helps me to take out any common factors, as well as make the lead term positive. I would make it...
-a(20a^2-13a-15)
...and then try to solve. I get...
-a(5a+3)(4a-5)
2007-10-11 12:35:37 · answer #3 · answered by mathguru 3 · 0⤊ 0⤋
-20a^3+15a+13a^2
a(-20a^2 +13a +15)
=a(5a+3)(-4a+5)
2007-10-11 12:49:42 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
-20a³ + 15a + 13a²
-20a³ + 13a² + 15a
-a(20a² - 13a - 15)
-a(4a - 5)(5a + 3)
2007-10-11 12:37:00 · answer #5 · answered by Marvin 4 · 0⤊ 0⤋