x^4-13x^3+42x^2+36x-216?

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What are the rational zeros of this polynomial and what is the factor with the zeros?

2007-10-11 05:17:58 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

You could use synthetic division to find that:

x^4-13x^3+42x^2+36x-216 = (x-6)^2*(x-3)*(x+2)
So:

6 twice
3
-2

2007-10-11 05:29:11 · answer #1 · answered by oscarD 3 · 0⤊ 0⤋

x^4-13x^3+42x^2+36x-216 =(x+2)(x-3)(x-6)^2
The four rational roots are -2,3, 6, and 6.

2007-10-11 12:34:18 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋