2007-10-11 03:14:32 · 5 answers · asked by referencearea 2 in Science & Mathematics ➔ Mathematics
put f(x)=y then get x=...
y=1/(2x+3)
2x+3=1/y
2x=1/y -3=(1-3y)/y
x=(1-3y)/2y
so the inverse will be (1-3x)/2x
2007-10-11 03:23:31 · answer #1 · answered by mbdwy 5 · 0⤊ 0⤋
Set this up as y = 1/(2x+3), and express in x-terms:
2x+3 = 1/y, and 2x = 1/y - 3, and finally, x = 1/2(1/y - 3). So the inverse f-(x) = 1/2(1/x - 3)
2007-10-11 10:20:35 · answer #2 · answered by John V 6 · 0⤊ 0⤋
y = f(x) = 1 / (2x + 3)
Solve for x getting:
x = (1-3y)/(2y)
Interchange x and y getting:
y = (1-3x)/(2x) <-- Inverse
2007-10-11 10:38:16 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
y = 1 / (2x + 3)
inverse
x = 1 / (2y + 3)
2xy + 3x = 1
2xy = 1 - 3x
y = (1 - 3x)/2x
inverse function
f^(-1)(x) = (1 - 3x)/2x
2007-10-11 10:23:24 · answer #4 · answered by Marvin 4 · 0⤊ 0⤋
f-1(x) = (1 - 3x)/2x
2007-10-11 10:19:56 · answer #5 · answered by Bananaman 5 · 0⤊ 0⤋