I have looked on the site but cant find the right link to hide my ID when I am bidding.
2007-10-10 22:01:58 · 7 answers · asked by jlb 5 in Computers & Internet ➔ Other - Computers
You can't , It's up to the seller to set up the ad that way
2007-10-10 22:05:04 · answer #1 · answered by Anonymous · 2⤊ 0⤋
You can't unless you are bidding on something over £100 and then the system sets you as bidder 1, bidder 2, whatever. If you are buying christmas pressies or something you shouldn't, start a new id!!
2007-10-10 22:04:40 · answer #2 · answered by Sal*UK 7 · 0⤊ 0⤋
you can't unless you change your id the seller chooses whether or not to protect bidders id when they list their item. Set up another ID to bid.
2007-10-10 22:05:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋
you're top - EBAY are a shame !!! they're cutting-edge day charletans: - take off commercials without observe - no threat to fantastic - so loose shoppers no matter if or not they're incorrect or top - and nevertheless take your funds and stress you to undergo their mind washing route ! - not achieveable to talk something with a man or woman - they insist you're taking PayPal for you to take more desirable funds of you !! - lie to shoppers by using giving one hundred% comments to shoppers who as you say cant get unfavourable comments - thats a con to persuade us all that its more desirable than it truly is if all of us needs a type action - or different direct help to take action adverse to EBAY, enable me understand - we are able to replace it at the same time ! playstation sorry I cant truly answer your question - there are distinct different smaller information superhighway sites yet EBAY is the wonderful nicely-known - yet now abuse their position
2016-10-09 00:32:31 · answer #4 · answered by ? 3 · 0⤊ 0⤋
Only the seller can do this for you, as far as im aware.
2007-10-10 22:05:20 · answer #5 · answered by Anonymous · 0⤊ 0⤋
isn't this done automatically
2007-10-10 22:05:13 · answer #6 · answered by ? 6 · 0⤊ 0⤋
You can't.
2007-10-10 22:10:09 · answer #7 · answered by ? 4 · 0⤊ 0⤋