English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Hi I would like to know how to solve the linear system equation x+2y+z=a2 , x+ y + 3z=a ,3x+ 4y +7y =10 how to solve this type of Equation

2007-10-10 19:53:48 · 2 answers · asked by Nur S 1 in Science & Mathematics Mathematics

2 answers

Use Gaussian reduction and back-substitution, just like rou would any other linear system. But your results for x, y, and z will be 'parameterized' in terms of a. That is, each of them will be some linear function of a.

Doug

2007-10-10 20:00:08 · answer #1 · answered by doug_donaghue 7 · 0 0

You have to discuss this if it's necessary.

x+2y+z = a^2
-x-y-3z = -a
_________
y - 2z = a^2 - a


-3x-3 y -9z=-3a
3x+ 4y +7y =10
___________
y-2z = 10-3a

In both cases you got y-2z. So, this will make some sense if a^2 - a= 10-3a. Otherwise, the system will be incompatible

If a^2 + 2a - 10 = 0 (you have to find a so that the system is compatible), then you have an infinit solution set

Write to me if you have more doubts

Ilusion

2007-10-11 13:35:02 · answer #2 · answered by Ilusion 4 · 0 0

fedest.com, questions and answers