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sin^(1/2)xcosx-sin^(5/2)xcosx=cos^3x(sinx)^1/2

2007-10-10 17:38:01 · 2 answers · asked by unknown 2 in Science & Mathematics Mathematics

2 answers

you need to put spaces... so that the equations can be read properly... §

sin^(1/2)(x) cosx - sin^(5/2)(x) cosx ?=? cos^3(x) sin^(1/2)(x)

= [√sinx] [cosx - sin^2(x) cosx]
= [√sinx] [cos x] [1 - sin^2(x)]
= [√sinx] [cos x] [cos^2(x)]
= [cos^3(x)] [√sinx]

2007-10-10 17:59:12 · answer #1 · answered by Alam Ko Iyan 7 · 1 0

Proper spacing is useful.

sin^(1/2) x cos x - sin^(5/2) x cos x
sin^(1/2) x cos x - sin² x sin^(1/2) x cos x
(1 - sin² x) sin^(1/2) x cos x
cos² x sin^(1/2) x cos x
sin^(1/2) x cos³ x

2007-10-11 00:57:44 · answer #2 · answered by Pascal 7 · 0 0

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