Kinetic and Potential Energy?

Question

A 223 g particle is released from rest at point A on the inside of a smooth hemispherical bowl of radius R = 27.0 cm http://www.webassign.net/sercp/p5-65.gif

Find
a. its gravitational potential energy at A relative to B

b. its kinetic energy at B

c. its speed at B

d. its potential energy at C relative to B

e. its kinetic energy at C

Answer 1

a. its gravitational potential energy at A relative to B

PE=mgh
=0.223kg*0.27m*9.8m/sec^2
=0.59 Joules

b. its kinetic energy at B

=0.59 Joules


c. its speed at B

KE=0.59 Joules

KE=1/2 mv^2

1/2 mv^2=.59 Joules

v^2=.59*2/.223kg=5.29

v= 2.3 m/sec


d. its potential energy at C relative to B

PEc = MGHc

Hc=2/3H

PEc=2/3 PEa

PEc=.393 Joules


e. its kinetic energy at C

KEc=PEa-PEc
=.59-.393
=0.197 Joules

Per Samantha, below, made minor correction. Just started writting Newtons instead of Joules in the answer. Corrected them all :-)

Answer 2

To the answer above. your calculations are correct except a, b, d, and e are in Joules not Newtons.