"Approximately what mass of CuSO4 · 5H20 (250 g/mol) is required to prepare 250mL of 0.10 M Copper (II) Sulfate solution?"
Note: I would really appreciate it if someone could kind of, guide me through the steps, or show me the work, so that I can understand it better. I'm not able to understand that well in class, but after trying to get help on Y! Answers, I've seen that it really does help. (Thanks to the person who answered my last question, btw!)
2007-10-10 16:45:26 · 1 answers · asked by Mishal 2 in Science & Mathematics ➔ Chemistry
250mL of 0.10 M Copper (II) Sulfate <==> 0.25x0.10 = 0.025Mol of Copper (II) Sulfate
The formular mass of CuSO4·5H20 is the formular mass of CuSO4 PLUS the formular mass of 5H2O: 249.7 g/Mol.
0.025Mol times 249.7 g/Mol is your answer!
2007-10-11 17:26:15 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋