help!! please math is so hardd ... !!! Below is a square split into four rectangular parts. The areas of two o

Question

http://i40.photobucket.com/albums/e215/xxs3xp1stolxx/Picture6.png

Answer 1

Let the area above the 8 be y and let x be the area to the side of the 8.

x/35 = 8/y
xy = 280

Also x+y = k
such that 43+k = perfect square

We can obtain the following quadratic:
x^2 - kx + 280 = 0
So k^2 - 1120 must be a perfect square.

Satisfy yourself that k = 38.
x = 28
y = 10

The perfect square which is the entire area is 81

Answer 2

The area of the square is 81, the sides being 9. The rectange with area 8 has sides 2 and 4, while the rectange with area 35 has sides 7 and 5. Note that 2 + 7 = 4 + 5 = 9.

Answer 3

One rectangle has component of 35. on condition that all of us comprehend the factors might desire to be total numbers, then the measurements of this rectangle might desire to be the two a million and 35 or 5 and seven. comparable is going for the different rectangle. That one has component of 8, so the factors might desire to be the two a million and eight or 2 and four. the entire photograph is a sq., meaning the factors might desire to be equivalent. be conscious that the peak of the sq. is comparable to the (height of the 35 rectangle) plus the (height of the 8 rectangle). additionally, the width of the sq. is comparable to the (width of the 35 rectangle) plus the (width of the 8 rectangle). So.... which combos of measurements upload to a similar variety: 35 = 5 x 7 8 = 4 x 2 5 + 4 = 9 7 + 2 = 9 So, the two factors of the sq. is 9, so the section is 80 one.