multiply [6a^(1/2) - b^(-1/2)][3a^(1/2) + b^(1/2)]?

2007-10-10 15:34:31 · 2 answers · asked by mandy 1 in Science & Mathematics ➔ Mathematics

18*a+sqrt of a(6*sqrt of b-3/sqrt of b)-1

2007-10-10 15:41:59 · answer #1 · answered by jtkipfinger 2 · 0⤊ 0⤋

(6âa - 1/âb)(3âa + âb) ..... you sure about the b^(-1/2) in the 1st factor?
=
18a + 6â(ab) - (3âa)/âb - 1

2007-10-10 22:44:12 · answer #2 · answered by Philo 7 · 0⤊ 0⤋

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