Rotation/Cylinder?

Question

It has been suggested that rotating cylinders about 12 mi long and 6.3 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth?
? rad/s

Answer 1

If 32 ft/s^2 is still acceleration due to gravity
and 1 mi has 5280 feet

The centripital acceleration is
a=V^2/R
The angular speed is
W= V/ R then
V=WR

a= W^2 R
a=32 ft/s^2 on its inner surface

Finally
W= sqrt(a/R)

W= sqrt(32/ ((6.3/2) x 5280)
w=0.044 rad/sec
W=2.63 rpm