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I'm having some confusion on my AP Chem assignment, and it's due tomorrow! The question I'm stuck on is this:
What volume of 0.150 molar HCL is required to neutralize 25.0 milliliters of 0.120 molar Ba(OH)2?

I would greatly appreciate it if someone could teach me how to do this problem!

2007-10-10 14:36:42 · 1 answers · asked by Mishal 2 in Education & Reference Homework Help

1 answers

Balenced Reaction:
2HCl + Ba(OH)2 ==> BaCl2 + 2H2O
25.0 ml of 0.120 molar Ba(OH)2 <==> 0.025*0.12 = 0.003(Mol) of Ba(OH)2, which requires 2*0.003 Mol = 0.006 Mol HCl to neutralize.
0.006 Mol /(0.150 mol/L) is your answer!!

2007-10-11 17:31:58 · answer #1 · answered by Hahaha 7 · 0 0

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