x^2+24=-10x
or x^2+10x+24=0
You have to find two nos whose sum=10(b)
& whose product is 24(ac)for ax^2+bx+c=0
or x^2+4x+6x+24=0
or x(x+4)+6(x+4)=0
or (x+4)(x+6)=0
so either x+4=0 or x+6=0
so either x=-4 or x=-6 ans
2007-10-10 13:10:15
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answer #1
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answered by MAHAANIM07 4
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x^2 + 10x + 24 = 0 # pair of numbers multiplying to give 24 and adding to give 10 =(6,4) 6 x 4 = 24, 4 +6 = 10
(x+4)(x+6) = 0
solve each bracket
x = -4, x=-6
2007-10-10 13:08:57
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answer #2
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answered by Anonymous
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X^2 + 10x + 24 = 0
(X + 6) (X + 4) = 0
X= -6 and -4
(for future, you want to find 2 numbers that multiply to equal the last number in the equation which ALSO add up to the second number)
2007-10-10 13:08:01
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answer #3
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answered by a.pasternak 2
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x^2+10x+24=0
(x+6)(x+4)=0 (FOIL this if you want to check)
x = -6, x = -4
2007-10-10 13:10:25
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answer #4
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answered by Nate 2
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The formulation for ending up the sq. is (B/2A)squared. So once you subtract 8 from the two aspects, divide 10 by employing employing 2, that's 5, then sq. 5, that is 25. choose this permits!
2016-10-21 23:34:11
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answer #5
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answered by marolf 4
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x = -4
2007-10-10 13:07:34
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answer #6
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answered by Jamie L 1
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What's in it for me.
Do your own homework!
2007-10-10 13:08:14
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answer #7
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answered by castledunrobin 2
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do your own homework!
2007-10-10 13:08:01
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answer #8
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answered by 4 strings 7
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dunno not really good wit math
2007-10-10 13:07:26
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answer #9
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answered by Jr A 1
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