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Solve the quadratic equation by completing the square: x^2 + 24 = - 10x

2007-10-10 13:04:56 · 9 answers · asked by sara 1 in Science & Mathematics Mathematics

9 answers

x^2+24=-10x
or x^2+10x+24=0
You have to find two nos whose sum=10(b)
& whose product is 24(ac)for ax^2+bx+c=0
or x^2+4x+6x+24=0
or x(x+4)+6(x+4)=0
or (x+4)(x+6)=0
so either x+4=0 or x+6=0
so either x=-4 or x=-6 ans

2007-10-10 13:10:15 · answer #1 · answered by MAHAANIM07 4 · 0 0

x^2 + 10x + 24 = 0 # pair of numbers multiplying to give 24 and adding to give 10 =(6,4) 6 x 4 = 24, 4 +6 = 10
(x+4)(x+6) = 0
solve each bracket
x = -4, x=-6

2007-10-10 13:08:57 · answer #2 · answered by Anonymous · 1 0

X^2 + 10x + 24 = 0
(X + 6) (X + 4) = 0
X= -6 and -4

(for future, you want to find 2 numbers that multiply to equal the last number in the equation which ALSO add up to the second number)

2007-10-10 13:08:01 · answer #3 · answered by a.pasternak 2 · 1 1

x^2+10x+24=0

(x+6)(x+4)=0 (FOIL this if you want to check)

x = -6, x = -4

2007-10-10 13:10:25 · answer #4 · answered by Nate 2 · 0 0

The formulation for ending up the sq. is (B/2A)squared. So once you subtract 8 from the two aspects, divide 10 by employing employing 2, that's 5, then sq. 5, that is 25. choose this permits!

2016-10-21 23:34:11 · answer #5 · answered by marolf 4 · 0 0

x = -4

2007-10-10 13:07:34 · answer #6 · answered by Jamie L 1 · 0 1

What's in it for me.
Do your own homework!

2007-10-10 13:08:14 · answer #7 · answered by castledunrobin 2 · 0 2

do your own homework!

2007-10-10 13:08:01 · answer #8 · answered by 4 strings 7 · 0 2

dunno not really good wit math

2007-10-10 13:07:26 · answer #9 · answered by Jr A 1 · 0 2

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