the sum of 3 consecutive ODD integers is the same as 5 times the greatest of the integers. What are they?

Question

for the life of me i cannot get this problem. Even if someone just gives me the formula i can work from there.

Answer 1

okay, this problem sounds confusing, but it's really not.

1. Say the greatest number was x. Then the second greatest number would be x-2, since they are consecutive odd integers.
The smallest integer would be x-4.

2.Those three added together would be 5 times x.

3.so the equation is (x-4)+(x-2)+x=5x.

4.If you simplify the left side the equation will be 3x-6=5x. Now that sounds weird cause it seems that 3x is smaller than 5x, but we can go into negative numbers.

5. If we subtract 3x from both sides, it will be -6=2x. So x=-3!

6. If we check, -3+-5+-7=5*-3

Hope that answers your question!

Answer 2

Let the 3 integers be, respectively, 2n+1, 2n+3, 2n+5 with the last one being the greatest The sum should be 5 times the greates (2n+1) + (2n+3) + (2n+5) = 5(2n+5) where n is any integer that we need to solve for: 6n + 9 = 10n + 25 4n = -16 n = -4 The integers are: 2n+1 = 2(-4)+1 = -7 2n+3 = 2(-4)+3 = -5 2n+5 = 2(-4)+5 = -3

Answer 3

Let n be the first odd integer
Let n + 2 be the 2nd odd integer
Let n + 4 be the 3rd odd integer

n+(n+2)+(n+4) = 5(n+4)

3n + 6 = 5n + 20
2n = -14
n = -7

As a double-check:
-7 + -5 + -3 = -15
-3 * 5 = -15

So the integers are -7, -5, -3

Answer 4

the sums of any three consecutive digits is 3n, where the digits are described as
n -2, n, n+2 |odd numbers|

So your equation is:
3n = 5(n+2)

3n = 5n+10
n = -5
sequence: -7, -5, -3

Answer 5

Formula is x+(x+2)+(x+4)=5(x+4)

continue and it's 3x+6=5x+20
solve to get x=7
the answer to question is 7,9,11