Twelve 5-liter cans, filled with syrup, weigh a total of 492 units. Each can, when empty, weigh 3 units. What is the weight of 1 liter of syrup alone (without a can)?
Explain.
2007-10-10 12:13:18 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
12 empty cans would weigh 36 units (12 * 3 units).
Subtract this from your total weight to get the weight of just the syrup.
492 - 36 = 456
That's the weight of 60 liters (12 * 5 liters), so divide to get the weight of 1 liter.
456/60 = 7.6 units
Another way to do this would be to start by dividing by 12 to get the weight of one full can:
492/12 = 41 units
Now subtract 3 units for the can:
41 - 3 = 38 units
And divide by 5 to get the weight of 1 liter:
38 / 5 = 7 3/5 units
Whew! Either way the answer is the same.
2007-10-10 12:20:32 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋