Please solve for the given variable and please show how you got the answer. There is No Possible Answer to one of the equations. I tried and i can't figure it out. Please help!Thank you!!
Equation:
5(z+1) + 6 = 3(8+z) + (2z - 13)
Equation:
5 - (8 - 3x) = (4x + 7) - x
2007-10-10 11:14:55 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Both the equations are can't be solved
Equation 1 ends up being
5z+11=5z+11
You can't solve for z
Equations 2 ends up being
3x-3=3x+7
or
3=7
Even more nonsense.
2007-10-10 11:24:33 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 1⤊ 0⤋
1) 5(z+1)+6=3(8+z)+(2z-13)
you would distribute
5z+5+6=24+3z+2z-13
add the numbers on the left side and the zs and numbers on right side
5z+11=11+5z
then subract 5z by 5z and subtract 11 by 11
0=0 hence solution
5-(8-3x)=(4x+7)-x
distribute
5-8+3x=4x+7-x
then sub 5-8 on the other side sub 4x-x
-3+3x=3x+7
add -3 to 7 then sub 3x to 3x
0=10 this one is not a solution
2007-10-10 11:41:05 · answer #2 · answered by rudybilliejo 2 · 0⤊ 0⤋
The first one is ALL REAL NUMBERS.
5(z)+5(1)+6= 24+3z+2z-13 *distribute*
5z+5+6=24+5z-13 *product of distribution*
5z+11=11+5z *combine like terms*
5z=5z *subtract 11*
z=z (1=1) *that means all real numbers.*
5-8+3x=4x+7-x *distribute*
-3+3x=3x+7 *combine like terms*
3x=3x+10 *add 3*
0=10 *subtract 3x*
NOT POSSIBLE.
2007-10-10 11:17:47 · answer #3 · answered by cc- ҉ - 4 · 0⤊ 0⤋
1) 5z+5+6=24+3z+2z-13
5z-3z-2z=24-13-5-6
0=0
thus, all values of z will satisy this equation.....both sides are equal
2)5-8+3x=4x+7-x
3x+x-4x=7-5+8
0=10
Thus no values of x will satisfy this equation.
2007-10-10 11:20:55 · answer #4 · answered by DUDE 2 · 0⤊ 0⤋