2007-10-10 10:55:42 · 6 answers · asked by JOHNNY J S 1 in Science & Mathematics ➔ Mathematics
factorize
(2n-3)(n-2)=0
n = 2 or 3/2
2007-10-10 10:59:56 · answer #1 · answered by norman 7 · 0⤊ 0⤋
2n^2-7n +6=0
solutions :
n = 2 and the other solution is 3/2
2007-10-10 11:00:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2n^2 -7n + 6 = 0
n = 2
n = 1.5
2007-10-10 12:51:51 · answer #3 · answered by Eduardo (lalo) Leal 2 · 0⤊ 0⤋
2n^2-7n+6=0
or 2n^2-4n-3n+6=0
or 2n(n-2)-3(n-2)=0
or (n-2)(2n-3)=0
so either n-2=0 or 2n-3=0
so either n=2 or n=3/2 ans
2007-10-10 11:06:12 · answer #4 · answered by MAHAANIM07 4 · 0⤊ 0⤋
( 2 n - 3 ) ( n - 2 ) = 0
n = 3 / 2 , n = 2
2007-10-10 11:11:49 · answer #5 · answered by Como 7 · 1⤊ 0⤋
n is an element of real numbers (basically any number)
2007-10-10 10:58:40 · answer #6 · answered by DUDE 2 · 0⤊ 0⤋