2007-10-10 10:38:27 · 7 answers · asked by Allen C 3 in Science & Mathematics ➔ Mathematics
the original question was to completely factor 64x^2+9... which I thought would be 8^2x^2+ 3^2...but cant go on any more... since (a+b)(a-b)= a^2-b^2... there is no set formula that can factor a^2+b^2...
2007-10-10 17:27:39 · update #1
Don't you need more than that to do something with it? Like, the other side of the equation?
2007-10-10 10:42:31 · answer #1 · answered by emily_brown18 6 · 0⤊ 0⤋
If you wish to factor x^2 + 1 you must use i where i^2 = -1
x^2+1 = (x+i)(x-i), Check by multiplying (use foil if you forget how {multiply: first terms + sum of outside and inside products + last term producs).
If you wish to solve x^2+1=0 subtract 1 from both sides to get
x^2 = -1 then take square roots to get
x= +/- sqrt(-1) = +/- i
The derivative of x^2+1 is 2x
The indefinite integral of x^2+1 is (x^3/3) +x+C
The graph of x^2+1 is a parabola with vertex at (0,1) opening up
2007-10-10 10:53:03 · answer #2 · answered by baja_tom 4 · 1⤊ 0⤋
assuming that the problem looks like this "x^2+1=0
the answer should be +- the square root of one
2007-10-10 10:43:21 · answer #3 · answered by jluster05 2 · 0⤊ 1⤋
(x+1)(x-1)
2007-10-10 10:45:32 · answer #4 · answered by abc123 3 · 1⤊ 1⤋
is that ur question? it depends the value of "x"
2007-10-10 10:42:27 · answer #5 · answered by Izzie 2 · 0⤊ 0⤋
do you mean solve for x or what they add to be?
2007-10-10 10:41:40 · answer #6 · answered by Anonymous · 0⤊ 0⤋
what is the question here?
2007-10-10 10:45:29 · answer #7 · answered by random person 4 · 0⤊ 0⤋