2007-10-10 10:36:03 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x=4y-1 or 2x - 4y = -1 ----- eq (1)
5y=2x+3 or 2x -5y = -3 ----- eq (2)
Subtract eq(2) from 1
-4y + 5y = -1 + 3
y = 2
therefore x = (4*2 - 1)/2= 7/2
2007-10-10 10:40:38 · answer #1 · answered by ib 4 · 0⤊ 1⤋
standard form has the x and y terms on the same side of the equation.
2x=4y-1
2x-4y=-1 (standard form)
5y=2x+3
-2x+5y=3 (standard form with x term first)
2007-10-10 10:41:13 · answer #2 · answered by Ed S 4 · 0⤊ 1⤋
2x = 4y - 1 = 2x - 4y + 1= 0
5y = 2x - 3 = -2x + 5y - 3 = 0
2007-10-10 11:36:06 · answer #3 · answered by Eduardo (lalo) Leal 2 · 0⤊ 0⤋
1) 2x-4y+1=0
2) -2x+5y-3=0
Satisfied?
2007-10-10 10:43:36 · answer #4 · answered by anordtug 6 · 0⤊ 0⤋
- 4y = -2x -1
5y = 2x + 3
That is the standard form. If you solve it, you may get the answer wrong, since the question says "put in standard form" rather than "solve".
2007-10-10 10:41:40 · answer #5 · answered by Anonymous · 0⤊ 0⤋
y = 2x/4 +1/4
and
y = 2x/5 +3/5
2007-10-10 10:39:21 · answer #6 · answered by Any day 6 · 1⤊ 0⤋
Here is my answer:
y = (2x+1)/4
the other one should look like this:
y = (2x+3)/5
2007-10-10 10:44:43 · answer #7 · answered by ♫ Shinedown ♫ 3 · 0⤊ 0⤋