A curve has the equation y=3x/2x-3 Find the equation of the normal to the curve at the origin?

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A curve has the equation y=3x/2x-3 Find the equation of the normal to the curve at the origin?

b) the normal at the origin cuts the curve again at O. Find the coordinates of P

Could you please explain how to do this because i have no idea how to do it. Thanks!

2007-10-10 09:43:18 · 1 answers · asked by Ryujin 3 in Science & Mathematics ➔ Mathematics

and show the working out...

2007-10-10 10:30:33 · update #1

1 answers

Do you mean y = 3x/(2x - 3)? If so, then y' = -1 at x = 0, so the tangent to the curve has slope -1.Therefore, the normal has slope 1, and the equation of the line through the origin with slope 1 is y = x.

2007-10-10 10:18:17 · answer #1 · answered by Tony 7 · 0⤊ 0⤋