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Why does differentiating "xlnx" give 1/e

2007-10-10 09:40:59 · 3 answers · asked by C4 Snake 3 in Science & Mathematics Mathematics

3 answers

It doesn't

If xlnx = uv by product rule:

u = x; du/dx = 1
v = lnx; dv/dx = 1/x
so using u.dv/dx + v.du/dx
= 1 + lnx

2007-10-10 09:50:47 · answer #1 · answered by Conquistador 1 · 0 0

Hey, Ol Whit, this is the second stupid question you have posed today. How come?

2007-10-10 10:26:10 · answer #2 · answered by Tony 7 · 0 0

i don't know but i think it gives
lnx + 1

sorry if this doesn't help

2007-10-10 09:46:20 · answer #3 · answered by 1101-1001 2 · 0 0

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