the question reads
solve the cubic equation
3x^3 - 7x^2 - 7x + 3 = 0
i get x=-3 and x= 11/3?? i am pretty sure this will be wrong so any solutions and how u got there will be much appreciated.
i have another which i will add if i get a responce to this one, i would like to try and get the other myself tho, thanks for any help
2007-10-10 08:56:29 · 8 answers · asked by AP12 2 in Science & Mathematics ➔ Mathematics
you should have 3 different values for x
3x^3 - 7x^2 - 7x = -3
x(3x^2 - 7x - 7) = -3
x(x-3.0887604324451327)(x+0.7554270991117994) = -3
umm....i think
2007-10-11 10:38:51 · answer #1 · answered by tsunamishadow 2 · 0⤊ 0⤋
How do you know for sure that your answers will be wrong? You should have a bit more confidence in your answers. Have you even tried checking your own answers? You know you can plug your answers in and you will know exactly if your answers are right or wrong. There should be no guessing involved.
As for answers, just by looking at it, I KNOW (for a fact) that x=-1 is a root of the given cubic. So divide the cubic by (x+1) and then use the quadratic formula to get the other two roots.
Done!
2007-10-10 09:06:43 · answer #2 · answered by The Prince 6 · 0⤊ 0⤋
i don't comprehend what you mean the "result" of the function does no longer replace & conscious of the "INPUTS". No theory what you attempt to ask. shall we are saying we've P = x² + 41x +141 and that i assist you to comprehend I even have chanced on a root of that, say its "Z". because of the fact it particularly is a quadratic, all of us comprehend that there are 2 roots. might you ask me for the different root or can we no longer at as quickly as be sure that the two roots are degenerate and we are in a position to furnish up finding for greater? it would be intense-high quality to comprehend. i'm confident there are different motives to tell apart between degenerate polynomial roots and non-degenerate ones, yet thats all I have been given. you're right, it particularly is a definition (and so arbitrary in that experience) no longer a evidence. yet I continually say, as quickly as you comprehend a discipline's terminology you comprehend 80% of the discipline. I seem to take into consideration some algorithms for fixing for polynomial roots might run into hardship with diverse roots. not sure if state-of-the-artwork algorithms have that undertaking. i'm speaking the place the Order of P is extensive.
2016-11-07 22:08:49 · answer #3 · answered by ? 4 · 0⤊ 0⤋
A hint - a cubic equation of this type requires 3 roots for value of x. Breakdown to format (x+a)(x+b)(X+c). a, b, c can be negative or positive.
2007-10-10 09:11:17 · answer #4 · answered by Anonymous · 0⤊ 0⤋
first i would try the divisors of 3
1 and 3
1 is almost correct ( just fill in )
-1 is correct and is thus a solution
next i divide the polynome by x+1 and obtain a quadratic expression,
that i will try to factor or use the abc formula.
2007-10-10 09:11:11 · answer #5 · answered by gjmb1960 7 · 0⤊ 0⤋
Well.....I have x = 1/3, -1 and 3.
I can explain how to do this, feel free to leave a message, but I did have to use A-level maths to do it.
:)
2007-10-10 09:16:34 · answer #6 · answered by lizard_magic 1 · 0⤊ 0⤋
typing
2007-10-10 09:01:22 · answer #7 · answered by a_talis_man 5 · 0⤊ 0⤋
sorry i can't help you, i got the same answer as u. is this algebra? i hate algebra. i'm taking algebra 2 next semester.
2007-10-10 09:06:45 · answer #8 · answered by Anonymous · 0⤊ 0⤋