Please expand the following brackets!!!!?

Question

(2x+y) (x+3y)

(3p+q) (3p+2q)

(3a-b) (2a+b)

(4p+2q) (3p-2q)


thanks so much i suck at algebra!!!

Answer 1

Expanding the brackets means multiplying the brackets together using F O I L.
F First terms - in each bracket the two left hand terms
O Outside terms - in each bracket the two at each end of the terms.
I Inside Terms - in each bracket the two terms adjaceent to the middle pair of brackets.
L Last terms - in each bracket the two right hand terms.

(2x + y )(x + 3y)
2x^2 + 6xy + xy + 3y^2 - collect like terms.
2x^2 + 7xy + 3y^2

(3p + q)(3p + 2q)
9p^2 + 6pq + 3pq + 2q^2
9p^2 + 9pq + 2q^2

(3a - b)(2a + b)
6a^2 + 3ab - 2ab -b^2
6a^2 + ab - b^2

(4p + 2q)(3p - 2q)
12p^2 - 8pq + 6pq - 4q^2
12p^2 -2pq - 4q^2

Hope that helps !!!!

Answer 2

(2x + y)(x + 3y)
= 2x(x + 3y) + y(x + 3y)
= 2x(x) + 2x(3y) + y(x) + y(3y)
= 2x^2 + 6xy + xy + 3y^2
= 2x^2 + 7xy + 3y^2

(3p+q) (3p+2q)
= 3p(3p+2q) + q(3p+2q)
= 9 p^2 + 6 pq + 3 pq + 2 q^2
= 9 p^2 + 9 pq + 2 q^2

(3a-b) (2a+b)
= 3a (2a + b) – b(2a + b)
= 6 a^2 + 3 ab – 2ab – b^2
= 6 a^2 + ab – b^2

(4p+2q) (3p-2q)
= 4p (3p-2q) + 2q (3p-2q)
= 12 p^2 – 8 pq + 6 pq – 4 q^2
= 12 p^2 – 2 pq – 4 q^2

Answer 3

2xsquared + 6xy + xy + 3y squared >>> 2x squared + 7xy + 3y squared

6p squared + 6pq + 3pq + 2q squared >>> 6p squared + 9pq + 2q squared


6a squared + 3ab -2ab -b squared >>> 6a Squared ab - b squared

12p squared -8pq + 6 pq - 4p squared >>> 12 p squared - 2pq - 4p squared

Answer 4

2x + y)(x + 3y)
= 2x(x + 3y) + y(x + 3y)
= 2x(x) + 2x(3y) + y(x) + y(3y)
= 2x^2 + 6xy + xy + 3y^2
= 2x^2 + 7xy + 3y^2

(3a - b)(2a + b)
= 3a(2a + b) - b(2a + b)
= 3a(2a) + 3a(b) - b(2a) - b(b)
= 6a^2 + 3ab - 2ab - b^2
= 6a^2 + ab - b^2

(3p+q)(3p+2q)
3p(3p+2q)+q(3p+2q)
3p.3p+3p.2q+q.3p+q.2q
9p^2+9pq+2q^2

Answer 5

2x² + 6xy + xy + 3y²
2x² + 7xy + 3y²

9p² + 3pq + 3pq + 2q²
9p² + 6pq + 2q²

6a² + 3ab - 2ab - b²
6a² + ab - b²

12p² - 8pq + 6pq - 4q²
12p² - 2pq - 4q²

Answer 6

typing

2x^2 + 6xy + yx + 3y^2
2x^2 + 7xy + 3y^2

9p^2+36pq+3pq+2q^2
9p^2 + 39pq + 2q^2

6a^2 + 3ab -2ab - b^2
6a^2 +ab - b^2

12p^2 - 8pq + 6pq - 4q^2
12p^2 - 2pq - 4q^2

hope this helps

Answer 7

(2x + y)(x + 3y)
= 2x(x + 3y) + y(x + 3y)
= 2x(x) + 2x(3y) + y(x) + y(3y)
= 2x^2 + 6xy + xy + 3y^2
= 2x^2 + 7xy + 3y^2

(3a - b)(2a + b)
= 3a(2a + b) - b(2a + b)
= 3a(2a) + 3a(b) - b(2a) - b(b)
= 6a^2 + 3ab - 2ab - b^2
= 6a^2 + ab - b^2

Now you try the other two on your own.

Answer 8

(2x+y) (x+3y)

Multiply each term in the left binomial by each term in the right binomial

(2x)(x) + (2x)(3y) + (y)(x) + (y)(3y)

2x^2 + 6xy + xy + 3y^2

2x^2 + 7xy + 3y^2

And do the same for each of the other problems

Answer 9

(x1 - 3)^2 + (x2 - 5)^2 = x1^2 - 6x1 + 9 + x2^2 - 10x2 + 25 = x1^2 - 6x1 - 10x2 + x2^2 + 34 = x1^2 + x2^2 - 2(3x1 + 5x2) + 34