English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

find the body's speed & acceleration of S= 8t - t^2 @ the endpoints of the interval 0<_ t <_ 5

2007-10-10 06:37:38 · 2 answers · asked by jewel7962002 1 in Science & Mathematics Physics

2 answers

v=8-2t
a= -2
SuB in the values of t
At t=0
v=8
a= -2
At t=5
v= - 2
a= -2

PS I got the values of v and a by differentiating the displacement function S with respect to t. The first derivative gives the velocity function; the second derivative gives the acceleration function.

2007-10-10 06:52:08 · answer #1 · answered by Anonymous · 0 0

I am assuming that this equation describes position versus time?

The velocity is
ds(t)/dt=v(t)
v(t)=8-2*t

Acceleration is
dv(t)/dt
a(t)=-2

at t=0
s(0)=0
v(0)=8
a(0)=-2

at t=5
s(5)=40-25
v(5)=8-10
a(5)=-2

j

2007-10-10 13:53:51 · answer #2 · answered by odu83 7 · 0 0

fedest.com, questions and answers