In rectangle ABCD, AC = 20, BC = 12, DC = 3x – y. and AD = 2x + y. Solve for x and y. Show all work to receive credit.
2007-10-10 05:53:46 · 6 answers · asked by Esther R 1 in Science & Mathematics ➔ Mathematics
AD=BC
2x+y=12
DC=AB
3x-y=sqrt(20^2-12^2)
=sqrt(16^2)
=16
(2x+y)+(3x-y)=12+16
5x=28
x=28/5
y=BC-2x
=12-56/5
=4/5
2007-10-11 09:28:22 · answer #1 · answered by Mugen is Strong 7 · 0⤊ 0⤋
First find AB by the pythagorean theorem (sqrt (20^2 - 12^2))
This equals DC which is 3x-y, and BC which is12 equals AD which is 2x + y, so write those two equations and eliminate one of the variables (y will be easy to eliminate).
2007-10-10 06:03:52 · answer #2 · answered by hayharbr 7 · 1⤊ 0⤋
AD=BC so 2x+y=12
AB=sqrt(400-144)=16= 3x-y
so
2x+y=12
3x-y=16
sum
5x=28 so x= 28/5 and y= 84/5-80/5=4/5
2007-10-10 06:10:01 · answer #3 · answered by santmann2002 7 · 1⤊ 0⤋
x^x + y^y ? x^y + y^x If the equality component is inspected then the equation could be written (x^x - x^y) - (y^x - y^y) = 0 Which has the answer x = y (notice : the answer x = y = 0 isn't allowed) The Inequality fact could be written :- (x^x - x^y) > (y^x - y^y) it rather is sparkling that the answer to this inequality happens while x > y and x >a million hence the preliminary fact is valid provided x ? y and x > a million
2016-12-29 03:11:49 · answer #4 · answered by ? 3 · 0⤊ 0⤋
ab = sqrt ( 20^2-12^2)
2007-10-10 06:04:21 · answer #5 · answered by harry m 6 · 1⤊ 0⤋
AC = BD
AB = CD
20 = 3x - y
12 = 2x+ y
x = 32/5
y = -4/5
2007-10-10 06:02:12 · answer #6 · answered by Ivan D 5 · 0⤊ 2⤋