0.2 + r = 0.2r − 0.06 + 0.3r
Fist, let's simplify the right side side:
r + 0.2 = 0.5r − 0.06
Next, isolate r and simplify.
(r + 0.2) - 0.5r - 0.2 = (0.5r − 0.06) -0.5r - 0.2
r - 0.5r = -0.06 - 0.2
0.5r = -0.26
(0.5r) / 0.5 = (-0.26) / 0.5
r = -0.52
2007-10-10 05:10:56
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answer #1
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answered by invincibleshield 2
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0.2 + r = 0.2r − 0.06 + 0.3r
put like terms together first. Remember to change the sign when taking a term to the other side.
-0.2r-0.3r+r = -0.06-0.2 ------> now just do the math
0.5r = -.26 -------> to isolate the r we need to divide by its coefficient, which in this case would be 0.5.
0.5r/0.5 = -.26/0.5 -------> remeber that what you do to the left you must do to the right, so divide both sides by 0.5.
r = -0.52
2007-10-10 05:42:14
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answer #2
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answered by itsSCIENCE 2
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0.2 + r = 0.2r − 0.06 + 0.3r
r - 0.5r = -0.06 - 0.2
0.5r = -0.26
... 0.5 is 1/2, so lets double everything
r = -0.52
2007-10-10 05:13:37
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answer #3
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answered by David F 5
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0.2 + r = 0.2r - 0.06 + 0.3r
0.2 + r = 0.5r - 0.06
r - 0.5r = -0.06 - 0.2
0.5r = -0.26
r = -0.52
2007-10-10 05:18:00
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answer #4
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answered by Xiomy 6
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20 + 100r = 20r - 6 + 30r
50r = - 26
r = - 26 / 50
r = - 13 / 25
2007-10-13 05:42:35
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answer #5
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answered by Como 7
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0.2+r=0.2r-0.06+0.3r
0.2+r=0.5r+0.06
.26= -0.5r
-0.52=r
Some people can do simple math.
2007-10-10 05:20:49
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answer #6
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answered by Seba 2
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0.2 + r = 0.2r - 0.06 + 0.3r
1.5 r = - 0.26
r = - 0.26 / 1.5 = - 0.17333 (to 5 dp)
2007-10-10 05:11:10
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answer #7
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answered by Doctor Q 6
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Call some friends over and urinate over your clothes and make it some sort of event/accomplishment in your life.
2016-05-20 23:31:27
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answer #8
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answered by rosie 3
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1.) combine like terms ------ .2+ r = 0.5r-.06
2.) get variables to one side and constants to the other -----
.26= -0.5r
3.) solve for r .26/-0.5 = r
r = -.52
2007-10-10 05:14:37
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answer #9
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answered by Anonymous
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There should def be a limit on what can be asked...Why dont you do YOUR OWN HOMEWORK instead of having the "real smart people" answer it for you.
2007-10-10 05:12:11
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answer #10
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answered by mdnhs01 3
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