If the perimeter of isosceles triangle ABC is 20 and the length of side AC is 8, what is one possible value for the length of side BC?
2007-10-10 04:59:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
let bc=ab
by that way BC=6
2007-10-10 05:03:41 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Ok, let's see. Isoceles triangles = 2 sides are the same length
AC + AB + BC = 20
Let AC = BC = 8
Let AC not equal to BC
so AC=AB = 8
8 + 8 + BC = 20
BC = 4
Good luck!
2007-10-10 05:04:09 · answer #2 · answered by alrivera_1 4 · 0⤊ 0⤋
I believe that this is the longer side. So 20-8/2 is 6 for the side.
2007-10-10 05:09:07 · answer #3 · answered by Gary H 1 · 0⤊ 0⤋
if AC is the base, 8 + 2BC = 20, 2BC = 12, BC = 6
if AC is one of the sides, 2(8) + BC = 20, 16 + BC = 20, BC = 4.
2007-10-10 05:07:19 · answer #4 · answered by Philo 7 · 3⤊ 0⤋