help
2007-10-10 04:56:58 · 5 answers · asked by Robby R 1 in Science & Mathematics ➔ Mathematics
First and second are right triangles, third one is not:
41 = SQRT (9^2 + 41^2)
10 = SQRT (6^2 + 8^2)
5 is not equal to SQRT (1^2 + 3^2)
you need to sum the square of the shorter sides because the hypotenuse is always the larger side
2007-10-10 05:05:05 · answer #1 · answered by landonastar 3 · 0⤊ 0⤋
9² + 40² = 81 + 1600 = 1681 = 41² yes
6² + 8² = 36 + 48 = 100 = 10² yes
1² + 3² = 1 + 9 = 10 <> 25 = 5² no
2007-10-10 05:02:30 · answer #2 · answered by Philo 7 · 0⤊ 0⤋
Hai Robby R,
A triangle will be Rt. angled if the Square of the longest side will equal the sum of the squares of the other two sides.
In the examples,
a=9,b=40,c=41 is rt. angled triangle, because,
a^2 = 9^2 = 81
b^2 = 40^2 = 1600
c^2 = 41^2 = 1681
=> a^2 + b^2 = c^2
a=6,b=8,c=10is rt. angled triangle, because,
a^2 = 6^2 = 36
b^2 = 8^2 = 64
c^2 = 10^2 = 100
=> a^2 + b^2 = c^2
a=9,b=40,c=41 is NOT a rt. angled triangle, because,
a^2 = 1^2 = 1
b^2 = 3^2 = 9
c^2 = 5^2 = 25
=> a^2 + b^2 "Not"= c^2
2007-10-10 05:10:40 · answer #3 · answered by WishInvestor 3 · 0⤊ 0⤋
a=6, b=8, c=10 - Yes, that is a right-angled triangle
a=9, b=40, c=41 - Yes, that is a right-angled triangle
2007-10-10 05:10:34 · answer #4 · answered by mr_maths_man 3 · 0⤊ 0⤋
check if a^2 + b^2 = c^2, if so, then it is a right triangle:) where a,b
a=6, b=8, c=10 is a right triangle...
a=1,b=3, c=5 is not.
Just solve for the first one:)
2007-10-10 05:03:59 · answer #5 · answered by songlover 1 · 0⤊ 0⤋